What are the solutions to the equation solvefor a,a^2-2ab+4b^2=0 ?

The solutions to the equation solvefor a,a^2-2ab+4b^2=0 are a=b+sqrt(3)ib,a=b-sqrt(3)ib

Find the zeros of solvefor a,a^2-2ab+4b^2=0

The zeros of solvefor a,a^2-2ab+4b^2=0 are a=b+sqrt(3)ib,a=b-sqrt(3)ib

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solve for

a, a^{2} - 2 ab + 4 b^{2} = 0

a = b + 3 ib, a = b - 3 ib

Solution steps

a^{2} - 2 ab + 4 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 2 ba + 4 b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 b ) \pm ( - 2 b ) ^{2} - 4 \cdot 1 \cdot 4 b ^{2}}{2 \cdot 1}

Simplify

(- 2 b)^{2} - 4 \cdot 1 \cdot 4 b^{2} : 23 ib

a_{1, 2} = \frac{- ( - 2 b ) \pm 2 3 ib}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 b ) + 2 3 ib}{2 \cdot 1}, a_{2} = \frac{- ( - 2 b ) - 2 3 ib}{2 \cdot 1}

a = \frac{- ( - 2 b ) + 2 3 ib}{2 \cdot 1} : b + 3 ib

a = \frac{- ( - 2 b ) - 2 3 ib}{2 \cdot 1} : b - 3 ib

The solutions to the quadratic equation are:

a = b + 3 ib, a = b - 3 ib

- 0.5 x^{2} + 50 x - 600 = 0

x, 0 = 1.47 x^{2} - 13.2 x + 12.86

x, f (2 x - 1) = 4 x^{2} - 4 x + 5

8 q^{2} + 8 q - 4 = 3 q^{2}

d^{2} - 2 d - 4 = 0

What are the solutions to the equation solvefor a,a^2-2ab+4b^2=0 ?
The solutions to the equation solvefor a,a^2-2ab+4b^2=0 are a=b+sqrt(3)ib,a=b-sqrt(3)ib
Find the zeros of solvefor a,a^2-2ab+4b^2=0
The zeros of solvefor a,a^2-2ab+4b^2=0 are a=b+sqrt(3)ib,a=b-sqrt(3)ib