What are the solutions to the equation -3v^2+10v+5=-8v^2 ?

The solutions to the equation -3v^2+10v+5=-8v^2 are v=-1

Find the zeros of -3v^2+10v+5=-8v^2

The zeros of -3v^2+10v+5=-8v^2 are v=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 v^{2} + 10 v + 5 = - 8 v^{2}

v = - 1

Solution steps

- 3 v^{2} + 10 v + 5 = - 8 v^{2}

Move

8 v^{2}

to the left side

5 v^{2} + 10 v + 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 \cdot 5 = 0

v_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 5}

v = \frac{- 10}{2 \cdot 5}

\frac{- 10}{2 \cdot 5} = - 1

v = - 1

The solution to the quadratic equation is:

v = - 1

15 d^{2} - 29 d + 8 = - 4

x^{2} + 8 = - 1

x, 12 x^{2} - 3 y^{2} + 12 z^{2} + 6 x = 15

0.534 (0.5 - x)^{2} = x^{2}

x, z = x^{2} + x y + y^{2} - 3 x - 6 y

What are the solutions to the equation -3v^2+10v+5=-8v^2 ?
The solutions to the equation -3v^2+10v+5=-8v^2 are v=-1
Find the zeros of -3v^2+10v+5=-8v^2
The zeros of -3v^2+10v+5=-8v^2 are v=-1