What are the solutions to the equation 5y^2+y-2=0 ?

The solutions to the equation 5y^2+y-2=0 are y=(-1+sqrt(41))/(10),y=(-1-sqrt(41))/(10)

Find the zeros of 5y^2+y-2=0

The zeros of 5y^2+y-2=0 are y=(-1+sqrt(41))/(10),y=(-1-sqrt(41))/(10)

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5 y^{2} + y - 2 = 0

y = \frac{- 1 + 41}{10}, y = \frac{- 1 - 41}{10}

Decimal Notation

y = 0.54031 \dots, y = - 0.74031 \dots

Solution steps

5 y^{2} + y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 2) = 41

y_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 1 + 41}{2 \cdot 5}, y_{2} = \frac{- 1 - 41}{2 \cdot 5}

y = \frac{- 1 + 41}{2 \cdot 5} : \frac{- 1 + 41}{10}

y = \frac{- 1 - 41}{2 \cdot 5} : \frac{- 1 - 41}{10}

The solutions to the quadratic equation are:

y = \frac{- 1 + 41}{10}, y = \frac{- 1 - 41}{10}

6 x^{2} = 4 x + 9 x - 6

(x + 2)^{2} - 3 x + 2 (x - 5) = - 8

x, x^{2} + k x + 4 - k = 0

19 q^{2} - q - 2 = 4 q^{2}

3 m^{2} + 11 m + 9 = 0

What are the solutions to the equation 5y^2+y-2=0 ?
The solutions to the equation 5y^2+y-2=0 are y=(-1+sqrt(41))/(10),y=(-1-sqrt(41))/(10)
Find the zeros of 5y^2+y-2=0
The zeros of 5y^2+y-2=0 are y=(-1+sqrt(41))/(10),y=(-1-sqrt(41))/(10)