What are the solutions to the equation 19q^2-q-2=4q^2 ?

The solutions to the equation 19q^2-q-2=4q^2 are q= 2/5 ,q=-1/3

Find the zeros of 19q^2-q-2=4q^2

The zeros of 19q^2-q-2=4q^2 are q= 2/5 ,q=-1/3

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19 q^{2} - q - 2 = 4 q^{2}

q = \frac{2}{5}, q = - \frac{1}{3}

Decimal Notation

q = 0.4, q = - 0.33333 \dots

Solution steps

19 q^{2} - q - 2 = 4 q^{2}

Move

4 q^{2}

to the left side

15 q^{2} - q - 2 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 15 ( - 2 )}{2 \cdot 15}

(- 1)^{2} - 4 \cdot 15 (- 2) = 11

q_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 15}

Separate the solutions

q_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 15}, q_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 15}

q = \frac{- ( - 1 ) + 11}{2 \cdot 15} : \frac{2}{5}

q = \frac{- ( - 1 ) - 11}{2 \cdot 15} : - \frac{1}{3}

The solutions to the quadratic equation are:

q = \frac{2}{5}, q = - \frac{1}{3}

3 m^{2} + 11 m + 9 = 0

4 x^{2} - 17 x + 8 = - 2 x

5 x^{2} - 10 x - 3 x + 1 = - 7 x^{2} + 11

x, x^{2} y - 6 x y + 8 y = 1

4 (x - 1)^{2} = 28

What are the solutions to the equation 19q^2-q-2=4q^2 ?
The solutions to the equation 19q^2-q-2=4q^2 are q= 2/5 ,q=-1/3
Find the zeros of 19q^2-q-2=4q^2
The zeros of 19q^2-q-2=4q^2 are q= 2/5 ,q=-1/3