What are the solutions to the equation 4(x-1)^2=28 ?

The solutions to the equation 4(x-1)^2=28 are x=sqrt(7)+1,x=-sqrt(7)+1

Find the zeros of 4(x-1)^2=28

The zeros of 4(x-1)^2=28 are x=sqrt(7)+1,x=-sqrt(7)+1

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4 (x - 1)^{2} = 28

x = 7 + 1, x = - 7 + 1

Decimal Notation

x = 3.64575 \dots, x = - 1.64575 \dots

Solution steps

4 (x - 1)^{2} = 28

Divide both sides by

4

(x - 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 7 : x = 7 + 1

Solve

x - 1 = - 7 : x = - 7 + 1

The solutions to the quadratic equation are:

x = 7 + 1, x = - 7 + 1

(X - 5)^{2} - 9 = 0

(5 x - 3)^{2} = - 32

8 w^{2} - 14 w + 5 = 0

x^{2} + 3 n x + n + 1 = 0

2 x^{2} - 19 x + 24 = 0

What are the solutions to the equation 4(x-1)^2=28 ?
The solutions to the equation 4(x-1)^2=28 are x=sqrt(7)+1,x=-sqrt(7)+1
Find the zeros of 4(x-1)^2=28
The zeros of 4(x-1)^2=28 are x=sqrt(7)+1,x=-sqrt(7)+1