What are the solutions to the equation 16m^2+22m+3=6m ?

The solutions to the equation 16m^2+22m+3=6m are m=-1/4 ,m=-3/4

Find the zeros of 16m^2+22m+3=6m

The zeros of 16m^2+22m+3=6m are m=-1/4 ,m=-3/4

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16 m^{2} + 22 m + 3 = 6 m

m = - \frac{1}{4}, m = - \frac{3}{4}

Decimal Notation

m = - 0.25, m = - 0.75

Solution steps

16 m^{2} + 22 m + 3 = 6 m

Move

6 m

to the left side

16 m^{2} + 16 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 16 \cdot 3}{2 \cdot 16}

1 6^{2} - 4 \cdot 16 \cdot 3 = 8

m_{1, 2} = \frac{- 16 \pm 8}{2 \cdot 16}

Separate the solutions

m_{1} = \frac{- 16 + 8}{2 \cdot 16}, m_{2} = \frac{- 16 - 8}{2 \cdot 16}

m = \frac{- 16 + 8}{2 \cdot 16} : - \frac{1}{4}

m = \frac{- 16 - 8}{2 \cdot 16} : - \frac{3}{4}

The solutions to the quadratic equation are:

m = - \frac{1}{4}, m = - \frac{3}{4}

m^{2} - 2 m - 39 = 7

30 s^{2} + 13 s - 10 = 0

90 = \frac{n ( n - 3 )}{2}

x^{2} - 6 x - 33 = - 4 x + 2

4 x^{2} + 6 x = 4

What are the solutions to the equation 16m^2+22m+3=6m ?
The solutions to the equation 16m^2+22m+3=6m are m=-1/4 ,m=-3/4
Find the zeros of 16m^2+22m+3=6m
The zeros of 16m^2+22m+3=6m are m=-1/4 ,m=-3/4