What are the solutions to the equation c^2+4c-17=c ?

The solutions to the equation c^2+4c-17=c are c=(-3+sqrt(77))/2 ,c=(-3-sqrt(77))/2

Find the zeros of c^2+4c-17=c

The zeros of c^2+4c-17=c are c=(-3+sqrt(77))/2 ,c=(-3-sqrt(77))/2

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c^{2} + 4 c - 17 = c

c = \frac{- 3 + 77}{2}, c = \frac{- 3 - 77}{2}

Decimal Notation

c = 2.88748 \dots, c = - 5.88748 \dots

Solution steps

c^{2} + 4 c - 17 = c

Move

c

to the left side

c^{2} + 3 c - 17 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 17) = 77

c_{1, 2} = \frac{- 3 \pm 77}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 3 + 77}{2 \cdot 1}, c_{2} = \frac{- 3 - 77}{2 \cdot 1}

c = \frac{- 3 + 77}{2 \cdot 1} : \frac{- 3 + 77}{2}

c = \frac{- 3 - 77}{2 \cdot 1} : \frac{- 3 - 77}{2}

The solutions to the quadratic equation are:

c = \frac{- 3 + 77}{2}, c = \frac{- 3 - 77}{2}

4 x^{2} - 6 x - 10 = 0

6 x^{2} + 15 x = 10 + 4 x

(2 x + 10)^{2} = 16

- 15 x^{2} + 47 = - 13

0 = 5 x^{2} - 5

What are the solutions to the equation c^2+4c-17=c ?
The solutions to the equation c^2+4c-17=c are c=(-3+sqrt(77))/2 ,c=(-3-sqrt(77))/2
Find the zeros of c^2+4c-17=c
The zeros of c^2+4c-17=c are c=(-3+sqrt(77))/2 ,c=(-3-sqrt(77))/2