What are the solutions to the equation 4x^2+12x-44=0 ?

The solutions to the equation 4x^2+12x-44=0 are x=(-3+sqrt(53))/2 ,x=-(3+sqrt(53))/2

Find the zeros of 4x^2+12x-44=0

The zeros of 4x^2+12x-44=0 are x=(-3+sqrt(53))/2 ,x=-(3+sqrt(53))/2

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4 x^{2} + 12 x - 44 = 0

x = \frac{- 3 + 53}{2}, x = - \frac{3 + 53}{2}

Decimal Notation

x = 2.14005 \dots, x = - 5.14005 \dots

Solution steps

4 x^{2} + 12 x - 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 44 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 44) = 453

x_{1, 2} = \frac{- 12 \pm 4 53}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 53}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 53}{2 \cdot 4}

x = \frac{- 12 + 4 53}{2 \cdot 4} : \frac{- 3 + 53}{2}

x = \frac{- 12 - 4 53}{2 \cdot 4} : - \frac{3 + 53}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 53}{2}, x = - \frac{3 + 53}{2}

21 = 7 x^{2}

x, x^{2} - x y + y^{3} = 4

4 v^{2} - 5 v - 1 = 4 v

(m - 2) x^{2} - (m + 5) x + 8 = 0

3 t^{2} = 12 + 5 t

What are the solutions to the equation 4x^2+12x-44=0 ?
The solutions to the equation 4x^2+12x-44=0 are x=(-3+sqrt(53))/2 ,x=-(3+sqrt(53))/2
Find the zeros of 4x^2+12x-44=0
The zeros of 4x^2+12x-44=0 are x=(-3+sqrt(53))/2 ,x=-(3+sqrt(53))/2