What are the solutions to the equation (4x+3)(x-8)+(x-1)(4x+3)=0 ?

The solutions to the equation (4x+3)(x-8)+(x-1)(4x+3)=0 are x= 9/2 ,x=-3/4

Find the zeros of (4x+3)(x-8)+(x-1)(4x+3)=0

The zeros of (4x+3)(x-8)+(x-1)(4x+3)=0 are x= 9/2 ,x=-3/4

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(4 x + 3) (x - 8) + (x - 1) (4 x + 3) = 0

x = \frac{9}{2}, x = - \frac{3}{4}

Decimal Notation

x = 4.5, x = - 0.75

Solution steps

(4 x + 3) (x - 8) + (x - 1) (4 x + 3) = 0

Expand

(4 x + 3) (x - 8) + (x - 1) (4 x + 3) : 8 x^{2} - 30 x - 27

8 x^{2} - 30 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 8 ( - 27 )}{2 \cdot 8}

(- 30)^{2} - 4 \cdot 8 (- 27) = 42

x_{1, 2} = \frac{- ( - 30 ) \pm 42}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 42}{2 \cdot 8}, x_{2} = \frac{- ( - 30 ) - 42}{2 \cdot 8}

x = \frac{- ( - 30 ) + 42}{2 \cdot 8} : \frac{9}{2}

x = \frac{- ( - 30 ) - 42}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - \frac{3}{4}

3 n^{2} - 5 n + 3 = 0

2 x^{2} + 3 x = 7 - 5 x

- 9 n (5 n - 5) = 0

3 x^{2} + 10 x - 4 = - x

(x - 8) (2 x + 10) = (x + 2) (x - 1)

What are the solutions to the equation (4x+3)(x-8)+(x-1)(4x+3)=0 ?
The solutions to the equation (4x+3)(x-8)+(x-1)(4x+3)=0 are x= 9/2 ,x=-3/4
Find the zeros of (4x+3)(x-8)+(x-1)(4x+3)=0
The zeros of (4x+3)(x-8)+(x-1)(4x+3)=0 are x= 9/2 ,x=-3/4