What are the solutions to the equation m^2+1=3 ?

The solutions to the equation m^2+1=3 are m=sqrt(2),m=-sqrt(2)

Find the zeros of m^2+1=3

The zeros of m^2+1=3 are m=sqrt(2),m=-sqrt(2)

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m^{2} + 1 = 3

m = 2, m = - 2

Decimal Notation

m = 1.41421 \dots, m = - 1.41421 \dots

Solution steps

m^{2} + 1 = 3

Move

1

to the right side

m^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 2, m = - 2

x^{2} + 6 x + 41 = 0

4 k^{2} - 4 k = 0

x^{2} - 7 x = 4

x, y^{3} = 1 - x^{2}

9 w^{2} + 17 w + 12 = 3 w^{2}

What are the solutions to the equation m^2+1=3 ?
The solutions to the equation m^2+1=3 are m=sqrt(2),m=-sqrt(2)
Find the zeros of m^2+1=3
The zeros of m^2+1=3 are m=sqrt(2),m=-sqrt(2)