What are the solutions to the equation 4x^2+16x=4x-9 ?

The solutions to the equation 4x^2+16x=4x-9 are x=-3/2

Find the zeros of 4x^2+16x=4x-9

The zeros of 4x^2+16x=4x-9 are x=-3/2

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4 x^{2} + 16 x = 4 x - 9

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

4 x^{2} + 16 x = 4 x - 9

Move

9

to the left side

4 x^{2} + 16 x + 9 = 4 x

Move

4 x

to the left side

4 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

x = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

- x^{2} - 2 x

3 (x^{2} - 2) = - 3 x

x^{2} + x = 156

x^{2} + \frac{1}{3} = \frac{7}{6} x

4 v^{2} + 23 v + 16 = 1

What are the solutions to the equation 4x^2+16x=4x-9 ?
The solutions to the equation 4x^2+16x=4x-9 are x=-3/2
Find the zeros of 4x^2+16x=4x-9
The zeros of 4x^2+16x=4x-9 are x=-3/2