What are the solutions to the equation 3(x^2-2)=-3x ?

The solutions to the equation 3(x^2-2)=-3x are x=1,x=-2

Find the zeros of 3(x^2-2)=-3x

The zeros of 3(x^2-2)=-3x are x=1,x=-2

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3 (x^{2} - 2) = - 3 x

x = 1, x = - 2

Solution steps

3 (x^{2} - 2) = - 3 x

Expand

3 (x^{2} - 2) : 3 x^{2} - 6

3 x^{2} - 6 = - 3 x

Move

3 x

to the left side

3 x^{2} - 6 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 6) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 3}, x_{2} = \frac{- 3 - 9}{2 \cdot 3}

x = \frac{- 3 + 9}{2 \cdot 3} : 1

x = \frac{- 3 - 9}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

x^{2} + x = 156

x^{2} + \frac{1}{3} = \frac{7}{6} x

4 v^{2} + 23 v + 16 = 1

x^{2} + 12 x = 72

2 k^{2} + 15 k + 19 = 0

What are the solutions to the equation 3(x^2-2)=-3x ?
The solutions to the equation 3(x^2-2)=-3x are x=1,x=-2
Find the zeros of 3(x^2-2)=-3x
The zeros of 3(x^2-2)=-3x are x=1,x=-2