What are the solutions to the equation x^2+12x=72 ?

The solutions to the equation x^2+12x=72 are x=6(sqrt(3)-1),x=-6(1+sqrt(3))

Find the zeros of x^2+12x=72

The zeros of x^2+12x=72 are x=6(sqrt(3)-1),x=-6(1+sqrt(3))

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x^{2} + 12 x = 72

x = 6 (3 - 1), x = - 6 (1 + 3)

Decimal Notation

x = 4.39230 \dots, x = - 16.39230 \dots

Solution steps

x^{2} + 12 x = 72

Move

72

to the left side

x^{2} + 12 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 72) = 123

x_{1, 2} = \frac{- 12 \pm 12 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 12 3}{2 \cdot 1}, x_{2} = \frac{- 12 - 12 3}{2 \cdot 1}

x = \frac{- 12 + 12 3}{2 \cdot 1} : 6 (3 - 1)

x = \frac{- 12 - 12 3}{2 \cdot 1} : - 6 (1 + 3)

The solutions to the quadratic equation are:

x = 6 (3 - 1), x = - 6 (1 + 3)

2 k^{2} + 15 k + 19 = 0

2 x^{2} - 1 = 3 x + 4

x^{2} - \frac{10}{3} x + 1 = 0

y^{2} + 16 y + 13 = 0

6 x^{2} + 3 x = 1 + 2 x

What are the solutions to the equation x^2+12x=72 ?
The solutions to the equation x^2+12x=72 are x=6(sqrt(3)-1),x=-6(1+sqrt(3))
Find the zeros of x^2+12x=72
The zeros of x^2+12x=72 are x=6(sqrt(3)-1),x=-6(1+sqrt(3))