What are the solutions to the equation -x^2+1.5x+5=-5 ?

The solutions to the equation -x^2+1.5x+5=-5 are x=-5/2 ,x=4

Find the zeros of -x^2+1.5x+5=-5

The zeros of -x^2+1.5x+5=-5 are x=-5/2 ,x=4

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- x^{2} + 1.5 x + 5 = - 5

x = - \frac{5}{2}, x = 4

Decimal Notation

x = - 2.5, x = 4

Solution steps

- x^{2} + 1.5 x + 5 = - 5

Multiply both sides by

10

- 10 x^{2} + 15 x + 50 = - 50

Move

50

to the left side

- 10 x^{2} + 15 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 10 ) \cdot 100}{2 ( - 10 )}

1 5^{2} - 4 (- 10) \cdot 100 = 65

x_{1, 2} = \frac{- 15 \pm 65}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 15 + 65}{2 ( - 10 )}, x_{2} = \frac{- 15 - 65}{2 ( - 10 )}

x = \frac{- 15 + 65}{2 ( - 10 )} : - \frac{5}{2}

x = \frac{- 15 - 65}{2 ( - 10 )} : 4

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = 4

x^{2} + (- 7) x + 10 = 0

(2 + 3 t)^{2} + (1 - t)^{2} + (1 + 2 t)^{2} = 6

a, (a + b)^{2} = d

- r^{2} - 3 r - 2 = - 5 r^{2}

(x + 1)^{2} + (\frac{( 0 - 1 ) ^{2}}{2}) = 1

What are the solutions to the equation -x^2+1.5x+5=-5 ?
The solutions to the equation -x^2+1.5x+5=-5 are x=-5/2 ,x=4
Find the zeros of -x^2+1.5x+5=-5
The zeros of -x^2+1.5x+5=-5 are x=-5/2 ,x=4