What are the solutions to the equation (x+1)^2+(((0-1)^2)/2)=1 ?

The solutions to the equation (x+1)^2+(((0-1)^2)/2)=1 are x=sqrt(1/2)-1,x=-sqrt(1/2)-1

Find the zeros of (x+1)^2+(((0-1)^2)/2)=1

The zeros of (x+1)^2+(((0-1)^2)/2)=1 are x=sqrt(1/2)-1,x=-sqrt(1/2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} + (\frac{( 0 - 1 ) ^{2}}{2}) = 1

x = \frac{1}{2} - 1, x = - \frac{1}{2} - 1

Decimal Notation

x = - 0.29289 \dots, x = - 1.70710 \dots

Solution steps

(x + 1)^{2} + (\frac{( 0 - 1 ) ^{2}}{2}) = 1

Move

(\frac{( 0 - 1 ) ^{2}}{2})

to the right side

(x + 1)^{2} = 1 - \frac{1}{2}

Simplify

1 - \frac{1}{2} : \frac{1}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = \frac{1}{2} : x = \frac{1}{2} - 1

Solve

x + 1 = - \frac{1}{2} : x = - \frac{1}{2} - 1

The solutions to the quadratic equation are:

x = \frac{1}{2} - 1, x = - \frac{1}{2} - 1

3 t^{2} - 8 t - 3 = 0

10 t^{2} + 33 t + 25 = 5

36 x^{2} + 24 x + 12 = 0

20 x^{2} - 26 x + 8 = 0

x^{2} - \frac{11}{3} x - 2 = 0

What are the solutions to the equation (x+1)^2+(((0-1)^2)/2)=1 ?
The solutions to the equation (x+1)^2+(((0-1)^2)/2)=1 are x=sqrt(1/2)-1,x=-sqrt(1/2)-1
Find the zeros of (x+1)^2+(((0-1)^2)/2)=1
The zeros of (x+1)^2+(((0-1)^2)/2)=1 are x=sqrt(1/2)-1,x=-sqrt(1/2)-1