What are the solutions to the equation x^2-11/3 x-2=0 ?

The solutions to the equation x^2-11/3 x-2=0 are x=(11+sqrt(193))/6 ,x=(11-sqrt(193))/6

Find the zeros of x^2-11/3 x-2=0

The zeros of x^2-11/3 x-2=0 are x=(11+sqrt(193))/6 ,x=(11-sqrt(193))/6

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x^{2} - \frac{11}{3} x - 2 = 0

x = \frac{11 + 193}{6}, x = \frac{11 - 193}{6}

Decimal Notation

x = 4.14874 \dots, x = - 0.48207 \dots

Solution steps

x^{2} - \frac{11}{3} x - 2 = 0

Multiply both sides by

3

3 x^{2} - 11 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 (- 6) = 193

x_{1, 2} = \frac{- ( - 11 ) \pm 193}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 193}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 193}{2 \cdot 3}

x = \frac{- ( - 11 ) + 193}{2 \cdot 3} : \frac{11 + 193}{6}

x = \frac{- ( - 11 ) - 193}{2 \cdot 3} : \frac{11 - 193}{6}

The solutions to the quadratic equation are:

x = \frac{11 + 193}{6}, x = \frac{11 - 193}{6}

25 k^{2} + 20 k + 3 = - 1

x, 2 x^{2} y - 2 x y = 0

y, x^{3} + x y^{2} - 2 y^{2} = 0

A x^{2} + 2 x + 3 = x^{2} - B x + C

x^{2} + 10 x + 5 = 30

What are the solutions to the equation x^2-11/3 x-2=0 ?
The solutions to the equation x^2-11/3 x-2=0 are x=(11+sqrt(193))/6 ,x=(11-sqrt(193))/6
Find the zeros of x^2-11/3 x-2=0
The zeros of x^2-11/3 x-2=0 are x=(11+sqrt(193))/6 ,x=(11-sqrt(193))/6