What are the solutions to the equation 5x^2-19x+6=-6x ?

The solutions to the equation 5x^2-19x+6=-6x are x=2,x= 3/5

Find the zeros of 5x^2-19x+6=-6x

The zeros of 5x^2-19x+6=-6x are x=2,x= 3/5

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5 x^{2} - 19 x + 6 = - 6 x

x = 2, x = \frac{3}{5}

Decimal Notation

x = 2, x = 0.6

Solution steps

5 x^{2} - 19 x + 6 = - 6 x

Move

6 x

to the left side

5 x^{2} - 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

(- 13)^{2} - 4 \cdot 5 \cdot 6 = 7

x_{1, 2} = \frac{- ( - 13 ) \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 7}{2 \cdot 5}, x_{2} = \frac{- ( - 13 ) - 7}{2 \cdot 5}

x = \frac{- ( - 13 ) + 7}{2 \cdot 5} : 2

x = \frac{- ( - 13 ) - 7}{2 \cdot 5} : \frac{3}{5}

The solutions to the quadratic equation are:

x = 2, x = \frac{3}{5}

(x - 25)^{2} = 36

x^{2} - 7 x + 10 = 0

(5 y + 6) (9 - y) = 0

4 k^{2} + 17 k + 18 = k^{2}

x, x^{2} - x y + y^{3} = 0

What are the solutions to the equation 5x^2-19x+6=-6x ?
The solutions to the equation 5x^2-19x+6=-6x are x=2,x= 3/5
Find the zeros of 5x^2-19x+6=-6x
The zeros of 5x^2-19x+6=-6x are x=2,x= 3/5