What are the solutions to the equation 4k^2+17k+18=k^2 ?

The solutions to the equation 4k^2+17k+18=k^2 are k=(-17+sqrt(73))/6 ,k=(-17-sqrt(73))/6

Find the zeros of 4k^2+17k+18=k^2

The zeros of 4k^2+17k+18=k^2 are k=(-17+sqrt(73))/6 ,k=(-17-sqrt(73))/6

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4 k^{2} + 17 k + 18 = k^{2}

k = \frac{- 17 + 73}{6}, k = \frac{- 17 - 73}{6}

Decimal Notation

k = - 1.40933 \dots, k = - 4.25733 \dots

Solution steps

4 k^{2} + 17 k + 18 = k^{2}

Move

k^{2}

to the left side

3 k^{2} + 17 k + 18 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 18 = 73

k_{1, 2} = \frac{- 17 \pm 73}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- 17 + 73}{2 \cdot 3}, k_{2} = \frac{- 17 - 73}{2 \cdot 3}

k = \frac{- 17 + 73}{2 \cdot 3} : \frac{- 17 + 73}{6}

k = \frac{- 17 - 73}{2 \cdot 3} : \frac{- 17 - 73}{6}

The solutions to the quadratic equation are:

k = \frac{- 17 + 73}{6}, k = \frac{- 17 - 73}{6}

x, x^{2} - x y + y^{3} = 0

2 w^{2} - 5 w - 9 = - 1

x^{2} + 9 x + 15 = - 5

5 x + 3 = - 2 x^{2}

2 x^{2} + 7 x + 52 = 0

What are the solutions to the equation 4k^2+17k+18=k^2 ?
The solutions to the equation 4k^2+17k+18=k^2 are k=(-17+sqrt(73))/6 ,k=(-17-sqrt(73))/6
Find the zeros of 4k^2+17k+18=k^2
The zeros of 4k^2+17k+18=k^2 are k=(-17+sqrt(73))/6 ,k=(-17-sqrt(73))/6