What are the solutions to the equation -16x^2+14x+4=0 ?

The solutions to the equation -16x^2+14x+4=0 are x=-(-7+sqrt(113))/(16),x=(7+sqrt(113))/(16)

Find the zeros of -16x^2+14x+4=0

The zeros of -16x^2+14x+4=0 are x=-(-7+sqrt(113))/(16),x=(7+sqrt(113))/(16)

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- 16 x^{2} + 14 x + 4 = 0

x = - \frac{- 7 + 113}{16}, x = \frac{7 + 113}{16}

Decimal Notation

x = - 0.22688 \dots, x = 1.10188 \dots

Solution steps

- 16 x^{2} + 14 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 16 ) \cdot 4}{2 ( - 16 )}

1 4^{2} - 4 (- 16) \cdot 4 = 2113

x_{1, 2} = \frac{- 14 \pm 2 113}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 14 + 2 113}{2 ( - 16 )}, x_{2} = \frac{- 14 - 2 113}{2 ( - 16 )}

x = \frac{- 14 + 2 113}{2 ( - 16 )} : - \frac{- 7 + 113}{16}

x = \frac{- 14 - 2 113}{2 ( - 16 )} : \frac{7 + 113}{16}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 113}{16}, x = \frac{7 + 113}{16}

- x^{2} + 6 x = - 1

9^{2} + x^{2} = 1 8^{2}

x^{2} + 55 = - 16 x - 5

2 x^{2} + 4 = 5 x + 2

x, x^{2} + y^{2} + z^{2} - 2 x - 4 y + 8 z + 17 = 0

What are the solutions to the equation -16x^2+14x+4=0 ?
The solutions to the equation -16x^2+14x+4=0 are x=-(-7+sqrt(113))/(16),x=(7+sqrt(113))/(16)
Find the zeros of -16x^2+14x+4=0
The zeros of -16x^2+14x+4=0 are x=-(-7+sqrt(113))/(16),x=(7+sqrt(113))/(16)