What are the solutions to the equation 5x^2-4x-8=5x+12 ?

The solutions to the equation 5x^2-4x-8=5x+12 are x=(9+sqrt(481))/(10),x=(9-sqrt(481))/(10)

Find the zeros of 5x^2-4x-8=5x+12

The zeros of 5x^2-4x-8=5x+12 are x=(9+sqrt(481))/(10),x=(9-sqrt(481))/(10)

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5 x^{2} - 4 x - 8 = 5 x + 12

x = \frac{9 + 481}{10}, x = \frac{9 - 481}{10}

Decimal Notation

x = 3.09317 \dots, x = - 1.29317 \dots

Solution steps

5 x^{2} - 4 x - 8 = 5 x + 12

Move

12

to the left side

5 x^{2} - 4 x - 20 = 5 x

Move

5 x

to the left side

5 x^{2} - 9 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

(- 9)^{2} - 4 \cdot 5 (- 20) = 481

x_{1, 2} = \frac{- ( - 9 ) \pm 481}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 481}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 481}{2 \cdot 5}

x = \frac{- ( - 9 ) + 481}{2 \cdot 5} : \frac{9 + 481}{10}

x = \frac{- ( - 9 ) - 481}{2 \cdot 5} : \frac{9 - 481}{10}

The solutions to the quadratic equation are:

x = \frac{9 + 481}{10}, x = \frac{9 - 481}{10}

8 x^{2} + 5 x - 4 = 2 x^{2} - 8 x + 1

5 x^{2} - 22 x - 4 = - 3 x

300 = - 0.32 q^{2} + 500

x, x^{2} = 2 y^{2} ln (y)

x, 3 x^{2} + 8 x y - 2 y^{2} - x + y + 6 = 0

What are the solutions to the equation 5x^2-4x-8=5x+12 ?
The solutions to the equation 5x^2-4x-8=5x+12 are x=(9+sqrt(481))/(10),x=(9-sqrt(481))/(10)
Find the zeros of 5x^2-4x-8=5x+12
The zeros of 5x^2-4x-8=5x+12 are x=(9+sqrt(481))/(10),x=(9-sqrt(481))/(10)