What are the solutions to the equation 300=-0.32q^2+500 ?

The solutions to the equation 300=-0.32q^2+500 are q=25,q=-25

Find the zeros of 300=-0.32q^2+500

The zeros of 300=-0.32q^2+500 are q=25,q=-25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

300 = - 0.32 q^{2} + 500

q = 25, q = - 25

Solution steps

300 = - 0.32 q^{2} + 500

Switch sides

- 0.32 q^{2} + 500 = 300

Move

500

to the right side

- 0.32 q^{2} = - 200

Divide both sides by

- 0.32

q^{2} = 625

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 625, q = - 625

625 = 25

- 625 = - 25

q = 25, q = - 25

x, x^{2} = 2 y^{2} ln (y)

x, 3 x^{2} + 8 x y - 2 y^{2} - x + y + 6 = 0

x^{2} + 3 x - 3 = 7 x + 9

4 (x - 3)^{2} = 80

- x^{2} - 2 x + 47 = 0

What are the solutions to the equation 300=-0.32q^2+500 ?
The solutions to the equation 300=-0.32q^2+500 are q=25,q=-25
Find the zeros of 300=-0.32q^2+500
The zeros of 300=-0.32q^2+500 are q=25,q=-25