What are the solutions to the equation 4(x-3)^2=80 ?

The solutions to the equation 4(x-3)^2=80 are x=2sqrt(5)+3,x=-2sqrt(5)+3

Find the zeros of 4(x-3)^2=80

The zeros of 4(x-3)^2=80 are x=2sqrt(5)+3,x=-2sqrt(5)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x - 3)^{2} = 80

x = 25 + 3, x = - 25 + 3

Decimal Notation

x = 7.47213 \dots, x = - 1.47213 \dots

Solution steps

4 (x - 3)^{2} = 80

Divide both sides by

4

(x - 3)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 20 : x = 25 + 3

Solve

x - 3 = - 20 : x = - 25 + 3

The solutions to the quadratic equation are:

x = 25 + 3, x = - 25 + 3

- x^{2} - 2 x + 47 = 0

6 x^{2} + 6 x - 2 = 0

(x) = 0.05 x^{2} + 10 x + 3000

x, - x^{2} + y^{2} + z^{2} = 1

8 x^{2} - 5 x + 87 = 7 x^{2} + 5 x

What are the solutions to the equation 4(x-3)^2=80 ?
The solutions to the equation 4(x-3)^2=80 are x=2sqrt(5)+3,x=-2sqrt(5)+3
Find the zeros of 4(x-3)^2=80
The zeros of 4(x-3)^2=80 are x=2sqrt(5)+3,x=-2sqrt(5)+3