What are the solutions to the equation 6x^2+6x-2=0 ?

The solutions to the equation 6x^2+6x-2=0 are x=(-3+sqrt(21))/6 ,x=-(3+sqrt(21))/6

Find the zeros of 6x^2+6x-2=0

The zeros of 6x^2+6x-2=0 are x=(-3+sqrt(21))/6 ,x=-(3+sqrt(21))/6

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6 x^{2} + 6 x - 2 = 0

x = \frac{- 3 + 21}{6}, x = - \frac{3 + 21}{6}

Decimal Notation

x = 0.26376 \dots, x = - 1.26376 \dots

Solution steps

6 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 2) = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 \cdot 6}, x_{2} = \frac{- 6 - 2 21}{2 \cdot 6}

x = \frac{- 6 + 2 21}{2 \cdot 6} : \frac{- 3 + 21}{6}

x = \frac{- 6 - 2 21}{2 \cdot 6} : - \frac{3 + 21}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 21}{6}, x = - \frac{3 + 21}{6}

(x) = 0.05 x^{2} + 10 x + 3000

x, - x^{2} + y^{2} + z^{2} = 1

8 x^{2} - 5 x + 87 = 7 x^{2} + 5 x

- 4 x^{2} + 17 x - 4 = 3 x + 2

4 x + (x + 2)^{2} = 3 x (x + 2)

What are the solutions to the equation 6x^2+6x-2=0 ?
The solutions to the equation 6x^2+6x-2=0 are x=(-3+sqrt(21))/6 ,x=-(3+sqrt(21))/6
Find the zeros of 6x^2+6x-2=0
The zeros of 6x^2+6x-2=0 are x=(-3+sqrt(21))/6 ,x=-(3+sqrt(21))/6