What are the solutions to the equation 2(x(x-5)+2(x-5)+2x(x-5))=48 ?

The solutions to the equation 2(x(x-5)+2(x-5)+2x(x-5))=48 are x=(13+sqrt(577))/6 ,x=(13-sqrt(577))/6

Find the zeros of 2(x(x-5)+2(x-5)+2x(x-5))=48

The zeros of 2(x(x-5)+2(x-5)+2x(x-5))=48 are x=(13+sqrt(577))/6 ,x=(13-sqrt(577))/6

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2 (x (x - 5) + 2 (x - 5) + 2 x (x - 5)) = 48

x = \frac{13 + 577}{6}, x = \frac{13 - 577}{6}

Decimal Notation

x = 6.17013 \dots, x = - 1.83680 \dots

Solution steps

2 (x (x - 5) + 2 (x - 5) + 2 x (x - 5)) = 48

Expand

2 (x (x - 5) + 2 (x - 5) + 2 x (x - 5)) : 6 x^{2} - 26 x - 20

6 x^{2} - 26 x - 20 = 48

Move

48

to the left side

6 x^{2} - 26 x - 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 6 ( - 68 )}{2 \cdot 6}

(- 26)^{2} - 4 \cdot 6 (- 68) = 2577

x_{1, 2} = \frac{- ( - 26 ) \pm 2 577}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 2 577}{2 \cdot 6}, x_{2} = \frac{- ( - 26 ) - 2 577}{2 \cdot 6}

x = \frac{- ( - 26 ) + 2 577}{2 \cdot 6} : \frac{13 + 577}{6}

x = \frac{- ( - 26 ) - 2 577}{2 \cdot 6} : \frac{13 - 577}{6}

The solutions to the quadratic equation are:

x = \frac{13 + 577}{6}, x = \frac{13 - 577}{6}

0.03 + 0.08 x - 0.012 x^{2} = 0

3600 = x^{2} - 160 x + 10000

x, \frac{x ^{2}}{3} + 3 y^{2} = 0

8 - (x - 1) (3 - x) = 4 (x - 1)

(x + 2)^{2} = 4 (2 x + 3)

What are the solutions to the equation 2(x(x-5)+2(x-5)+2x(x-5))=48 ?
The solutions to the equation 2(x(x-5)+2(x-5)+2x(x-5))=48 are x=(13+sqrt(577))/6 ,x=(13-sqrt(577))/6
Find the zeros of 2(x(x-5)+2(x-5)+2x(x-5))=48
The zeros of 2(x(x-5)+2(x-5)+2x(x-5))=48 are x=(13+sqrt(577))/6 ,x=(13-sqrt(577))/6