What are the solutions to the equation x^2-3x-9/4 =12 ?

The solutions to the equation x^2-3x-9/4 =12 are x=(3+sqrt(66))/2 ,x=(3-sqrt(66))/2

Find the zeros of x^2-3x-9/4 =12

The zeros of x^2-3x-9/4 =12 are x=(3+sqrt(66))/2 ,x=(3-sqrt(66))/2

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x^{2} - 3 x - \frac{9}{4} = 12

x = \frac{3 + 66}{2}, x = \frac{3 - 66}{2}

Decimal Notation

x = 5.56201 \dots, x = - 2.56201 \dots

Solution steps

x^{2} - 3 x - \frac{9}{4} = 12

Multiply both sides by

4

4 x^{2} - 12 x - 9 = 48

Move

48

to the left side

4 x^{2} - 12 x - 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 57 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 57) = 466

x_{1, 2} = \frac{- ( - 12 ) \pm 4 66}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 66}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 66}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 66}{2 \cdot 4} : \frac{3 + 66}{2}

x = \frac{- ( - 12 ) - 4 66}{2 \cdot 4} : \frac{3 - 66}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 66}{2}, x = \frac{3 - 66}{2}

2 x^{2} - 12 x + 17

3 x^{2} + x + 4 = - 9 x + 1

x, x^{2} + (1 - y)^{2} + 5 = 0

x, 7 x^{2} + 7 y^{2} - 2 x y - 6 x - 6 y = 9

- \frac{1}{2} x^{2} + 4 = x

What are the solutions to the equation x^2-3x-9/4 =12 ?
The solutions to the equation x^2-3x-9/4 =12 are x=(3+sqrt(66))/2 ,x=(3-sqrt(66))/2
Find the zeros of x^2-3x-9/4 =12
The zeros of x^2-3x-9/4 =12 are x=(3+sqrt(66))/2 ,x=(3-sqrt(66))/2