What are the solutions to the equation p^2+7p=-6 ?

The solutions to the equation p^2+7p=-6 are p=-1,p=-6

Find the zeros of p^2+7p=-6

The zeros of p^2+7p=-6 are p=-1,p=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^{2} + 7 p = - 6

p = - 1, p = - 6

Solution steps

p^{2} + 7 p = - 6

Move

6

to the left side

p^{2} + 7 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

p_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 7 + 5}{2 \cdot 1}, p_{2} = \frac{- 7 - 5}{2 \cdot 1}

p = \frac{- 7 + 5}{2 \cdot 1} : - 1

p = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

p = - 1, p = - 6

x^{2} - 0.4 x - 0.04 = 0

40 x^{2} + 33 x - 18 = 0

- 3 x^{2} - 5 = - x

- 8 x^{2} + 26 x - 15 = 0

x (x - 2) = 2 x - 2

What are the solutions to the equation p^2+7p=-6 ?
The solutions to the equation p^2+7p=-6 are p=-1,p=-6
Find the zeros of p^2+7p=-6
The zeros of p^2+7p=-6 are p=-1,p=-6