What are the solutions to the equation x^2+(-2)^2=1 ?

The solutions to the equation x^2+(-2)^2=1 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of x^2+(-2)^2=1

The zeros of x^2+(-2)^2=1 are x=sqrt(3)i,x=-sqrt(3)i

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x^{2} + (- 2)^{2} = 1

x = 3 i, x = - 3 i

Solution steps

x^{2} + (- 2)^{2} = 1

Expand

x^{2} + (- 2)^{2} : x^{2} + 4

x^{2} + 4 = 1

Move

4

to the right side

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

t, s t + 1 = t^{2} + 5

2 x^{2} + 8 x = - 2

x, x^{2} + x = y^{2} + y

x, x^{2} + 2 y^{2} + z^{2} - 4 x + 4 y - 2 z + 3 = 0

2 y^{2} - 5 y - 2 = 0

What are the solutions to the equation x^2+(-2)^2=1 ?
The solutions to the equation x^2+(-2)^2=1 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of x^2+(-2)^2=1
The zeros of x^2+(-2)^2=1 are x=sqrt(3)i,x=-sqrt(3)i