What are the solutions to the equation 2x^2+8x=-2 ?

The solutions to the equation 2x^2+8x=-2 are x=-2+sqrt(3),x=-2-sqrt(3)

Find the zeros of 2x^2+8x=-2

The zeros of 2x^2+8x=-2 are x=-2+sqrt(3),x=-2-sqrt(3)

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2 x^{2} + 8 x = - 2

x = - 2 + 3, x = - 2 - 3

Decimal Notation

x = - 0.26794 \dots, x = - 3.73205 \dots

Solution steps

2 x^{2} + 8 x = - 2

Move

2

to the left side

2 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 2 = 43

x_{1, 2} = \frac{- 8 \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 3}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 3}{2 \cdot 2}

x = \frac{- 8 + 4 3}{2 \cdot 2} : - 2 + 3

x = \frac{- 8 - 4 3}{2 \cdot 2} : - 2 - 3

The solutions to the quadratic equation are:

x = - 2 + 3, x = - 2 - 3

x, x^{2} + x = y^{2} + y

x, x^{2} + 2 y^{2} + z^{2} - 4 x + 4 y - 2 z + 3 = 0

2 y^{2} - 5 y - 2 = 0

- 7 x - 60 = x^{2} + 10 x

m x^{2} + (2 m + 5) x + (m + 3) = 0

What are the solutions to the equation 2x^2+8x=-2 ?
The solutions to the equation 2x^2+8x=-2 are x=-2+sqrt(3),x=-2-sqrt(3)
Find the zeros of 2x^2+8x=-2
The zeros of 2x^2+8x=-2 are x=-2+sqrt(3),x=-2-sqrt(3)