What are the solutions to the equation -7x-60=x^2+10x ?

The solutions to the equation -7x-60=x^2+10x are x=-5,x=-12

Find the zeros of -7x-60=x^2+10x

The zeros of -7x-60=x^2+10x are x=-5,x=-12

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- 7 x - 60 = x^{2} + 10 x

x = - 5, x = - 12

Solution steps

- 7 x - 60 = x^{2} + 10 x

Switch sides

x^{2} + 10 x = - 7 x - 60

Move

60

to the left side

x^{2} + 10 x + 60 = - 7 x

Move

7 x

to the left side

x^{2} + 17 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 60 = 7

x_{1, 2} = \frac{- 17 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 7}{2 \cdot 1}, x_{2} = \frac{- 17 - 7}{2 \cdot 1}

x = \frac{- 17 + 7}{2 \cdot 1} : - 5

x = \frac{- 17 - 7}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = - 5, x = - 12

m x^{2} + (2 m + 5) x + (m + 3) = 0

1 + x = x^{2} - 2

6 x^{2} + 13 x + 6 = 0

x^{2} + 5 x + 16 = 0

x^{2} - 11 x + 97 = 8 x + 7

What are the solutions to the equation -7x-60=x^2+10x ?
The solutions to the equation -7x-60=x^2+10x are x=-5,x=-12
Find the zeros of -7x-60=x^2+10x
The zeros of -7x-60=x^2+10x are x=-5,x=-12