What are the solutions to the equation 5-3x-x^2=3x^2+4x+3 ?

The solutions to the equation 5-3x-x^2=3x^2+4x+3 are x=-2,x= 1/4

Find the zeros of 5-3x-x^2=3x^2+4x+3

The zeros of 5-3x-x^2=3x^2+4x+3 are x=-2,x= 1/4

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5 - 3 x - x^{2} = 3 x^{2} + 4 x + 3

x = - 2, x = \frac{1}{4}

Decimal Notation

x = - 2, x = 0.25

Solution steps

5 - 3 x - x^{2} = 3 x^{2} + 4 x + 3

Move

3

to the left side

- x^{2} - 3 x + 2 = 3 x^{2} + 4 x

Move

4 x

to the left side

- x^{2} - 7 x + 2 = 3 x^{2}

Move

3 x^{2}

to the left side

- 4 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

(- 7)^{2} - 4 (- 4) \cdot 2 = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 ( - 4 )}, x_{2} = \frac{- ( - 7 ) - 9}{2 ( - 4 )}

x = \frac{- ( - 7 ) + 9}{2 ( - 4 )} : - 2

x = \frac{- ( - 7 ) - 9}{2 ( - 4 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = - 2, x = \frac{1}{4}

2 b^{2} + 11 b + 13 = 0

a, (a - b)^{2} = 64

x, x^{2} + y^{2} - 4 x - 10 y + 29 = 0

5 n^{2} - 3 n = 2

3 x^{2} + 7 x + 9 = 0

What are the solutions to the equation 5-3x-x^2=3x^2+4x+3 ?
The solutions to the equation 5-3x-x^2=3x^2+4x+3 are x=-2,x= 1/4
Find the zeros of 5-3x-x^2=3x^2+4x+3
The zeros of 5-3x-x^2=3x^2+4x+3 are x=-2,x= 1/4