What are the solutions to the equation 0=4x^2-72x ?

The solutions to the equation 0=4x^2-72x are x=18,x=0

Find the zeros of 0=4x^2-72x

The zeros of 0=4x^2-72x are x=18,x=0

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0 = 4 x^{2} - 72 x

x = 18, x = 0

Solution steps

0 = 4 x^{2} - 72 x

Switch sides

4 x^{2} - 72 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 72)^{2} - 4 \cdot 4 \cdot 0 = 72

x_{1, 2} = \frac{- ( - 72 ) \pm 72}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 72}{2 \cdot 4}, x_{2} = \frac{- ( - 72 ) - 72}{2 \cdot 4}

x = \frac{- ( - 72 ) + 72}{2 \cdot 4} : 18

x = \frac{- ( - 72 ) - 72}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 18, x = 0

0 = - \frac{1}{4} (x - 4)^{2} + 8

1521 = 13 x^{2}

x^{2} + x (x - 6) = 0

x, 3 x^{2} + 4 x - 4 = 0

4 y^{2} - 4 y + 5

What are the solutions to the equation 0=4x^2-72x ?
The solutions to the equation 0=4x^2-72x are x=18,x=0
Find the zeros of 0=4x^2-72x
The zeros of 0=4x^2-72x are x=18,x=0