What are the solutions to the equation 30x^2-420x+1470=0 ?

The solutions to the equation 30x^2-420x+1470=0 are x=7

Find the zeros of 30x^2-420x+1470=0

The zeros of 30x^2-420x+1470=0 are x=7

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30 x^{2} - 420 x + 1470 = 0

x = 7

Solution steps

30 x^{2} - 420 x + 1470 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 420 ) \pm ( - 420 ) ^{2} - 4 \cdot 30 \cdot 1470}{2 \cdot 30}

(- 420)^{2} - 4 \cdot 30 \cdot 1470 = 0

x_{1, 2} = \frac{- ( - 420 ) \pm 0}{2 \cdot 30}

x = \frac{- ( - 420 )}{2 \cdot 30}

\frac{- ( - 420 )}{2 \cdot 30} = 7

x = 7

The solution to the quadratic equation is:

x = 7

- 3 x^{2} + 7 x = - 2 x - 8

x + 1 = x^{2} - 1

- x^{2} - 2 x - 3 = - 2 x^{2}

x, 3 x^{2} + 3 y^{2} - 6 x + 12 y + 60 = 0

4 d^{2} + d + 1 = - 3 d

What are the solutions to the equation 30x^2-420x+1470=0 ?
The solutions to the equation 30x^2-420x+1470=0 are x=7
Find the zeros of 30x^2-420x+1470=0
The zeros of 30x^2-420x+1470=0 are x=7