What are the solutions to the equation 2400=-d^2+70d+1800 ?

The solutions to the equation 2400=-d^2+70d+1800 are d=10,d=60

Find the zeros of 2400=-d^2+70d+1800

The zeros of 2400=-d^2+70d+1800 are d=10,d=60

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2400 = - d^{2} + 70 d + 1800

d = 10, d = 60

Solution steps

2400 = - d^{2} + 70 d + 1800

Switch sides

- d^{2} + 70 d + 1800 = 2400

Move

2400

to the left side

- d^{2} + 70 d - 600 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 ( - 1 ) ( - 600 )}{2 ( - 1 )}

7 0^{2} - 4 (- 1) (- 600) = 50

d_{1, 2} = \frac{- 70 \pm 50}{2 ( - 1 )}

Separate the solutions

d_{1} = \frac{- 70 + 50}{2 ( - 1 )}, d_{2} = \frac{- 70 - 50}{2 ( - 1 )}

d = \frac{- 70 + 50}{2 ( - 1 )} : 10

d = \frac{- 70 - 50}{2 ( - 1 )} : 60

The solutions to the quadratic equation are:

d = 10, d = 60

x^{2} + 12 x = 4 x + 20

3 x^{2} - 1 = 26

\frac{1}{2} r^{2} - 6 r = 2

b = 4 c - s^{2}

- x^{2} + 4 x = \frac{3}{2} x

What are the solutions to the equation 2400=-d^2+70d+1800 ?
The solutions to the equation 2400=-d^2+70d+1800 are d=10,d=60
Find the zeros of 2400=-d^2+70d+1800
The zeros of 2400=-d^2+70d+1800 are d=10,d=60