What are the solutions to the equation 3(a-5)(a+2)=0 ?

The solutions to the equation 3(a-5)(a+2)=0 are a=5,a=-2

Find the zeros of 3(a-5)(a+2)=0

The zeros of 3(a-5)(a+2)=0 are a=5,a=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (a - 5) (a + 2) = 0

a = 5, a = - 2

Solution steps

3 (a - 5) (a + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - 5 = 0 or a + 2 = 0

Solve

a - 5 = 0 : a = 5

Solve

a + 2 = 0 : a = - 2

The solutions to the quadratic equation are:

a = 5, a = - 2

y, z = x^{2} y^{2} + x^{3} y

x, f x = x^{2}

(t) = - 0.0002 t^{2} + 0.06 t

36 t^{2} - 12 t + 1 = 0

(x + \frac{1}{3})^{2} = \frac{4}{9}

What are the solutions to the equation 3(a-5)(a+2)=0 ?
The solutions to the equation 3(a-5)(a+2)=0 are a=5,a=-2
Find the zeros of 3(a-5)(a+2)=0
The zeros of 3(a-5)(a+2)=0 are a=5,a=-2