What are the solutions to the equation 36t^2-12t+1=0 ?

The solutions to the equation 36t^2-12t+1=0 are t= 1/6

Find the zeros of 36t^2-12t+1=0

The zeros of 36t^2-12t+1=0 are t= 1/6

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36 t^{2} - 12 t + 1 = 0

t = \frac{1}{6}

Decimal Notation

t = 0.16666 \dots

Solution steps

36 t^{2} - 12 t + 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 36 \cdot 1}{2 \cdot 36}

(- 12)^{2} - 4 \cdot 36 \cdot 1 = 0

t_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 36}

t = \frac{- ( - 12 )}{2 \cdot 36}

\frac{- ( - 12 )}{2 \cdot 36} = \frac{1}{6}

t = \frac{1}{6}

The solution to the quadratic equation is:

t = \frac{1}{6}

(x + \frac{1}{3})^{2} = \frac{4}{9}

4 x^{2} - 6 x - 30 = 3 x^{2} + x

x^{2} = - 2 x + 1

- 3 p^{2} + 9 p + 4 = - 5 p^{2}

x, 4 x^{2} - 25 = 0

What are the solutions to the equation 36t^2-12t+1=0 ?
The solutions to the equation 36t^2-12t+1=0 are t= 1/6
Find the zeros of 36t^2-12t+1=0
The zeros of 36t^2-12t+1=0 are t= 1/6