What are the solutions to the equation -3p^2+9p+4=-5p^2 ?

The solutions to the equation -3p^2+9p+4=-5p^2 are p=-1/2 ,p=-4

Find the zeros of -3p^2+9p+4=-5p^2

The zeros of -3p^2+9p+4=-5p^2 are p=-1/2 ,p=-4

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- 3 p^{2} + 9 p + 4 = - 5 p^{2}

p = - \frac{1}{2}, p = - 4

Decimal Notation

p = - 0.5, p = - 4

Solution steps

- 3 p^{2} + 9 p + 4 = - 5 p^{2}

Move

5 p^{2}

to the left side

2 p^{2} + 9 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 4 = 7

p_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 9 + 7}{2 \cdot 2}, p_{2} = \frac{- 9 - 7}{2 \cdot 2}

p = \frac{- 9 + 7}{2 \cdot 2} : - \frac{1}{2}

p = \frac{- 9 - 7}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

p = - \frac{1}{2}, p = - 4

x, 4 x^{2} - 25 = 0

x^{2} - 4 x + 6 = 1

x^{2} - 4 x + 4 + x^{2} + 4 x + 4 = 3 x^{2} - x + x - 4

7 x^{2} - 3 x + 10 = 0

9 x^{2} - 42 x + 45 = 0

What are the solutions to the equation -3p^2+9p+4=-5p^2 ?
The solutions to the equation -3p^2+9p+4=-5p^2 are p=-1/2 ,p=-4
Find the zeros of -3p^2+9p+4=-5p^2
The zeros of -3p^2+9p+4=-5p^2 are p=-1/2 ,p=-4