What are the solutions to the equation 7x^2-3x+10=0 ?

The solutions to the equation 7x^2-3x+10=0 are x= 3/14+i(sqrt(271))/(14),x= 3/14-i(sqrt(271))/(14)

Find the zeros of 7x^2-3x+10=0

The zeros of 7x^2-3x+10=0 are x= 3/14+i(sqrt(271))/(14),x= 3/14-i(sqrt(271))/(14)

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7 x^{2} - 3 x + 10 = 0

x = \frac{3}{14} + i \frac{271}{14}, x = \frac{3}{14} - i \frac{271}{14}

Solution steps

7 x^{2} - 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 \cdot 10}{2 \cdot 7}

Simplify

(- 3)^{2} - 4 \cdot 7 \cdot 10 : 271 i

x_{1, 2} = \frac{- ( - 3 ) \pm 271 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 271 i}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 271 i}{2 \cdot 7}

x = \frac{- ( - 3 ) + 271 i}{2 \cdot 7} : \frac{3}{14} + i \frac{271}{14}

x = \frac{- ( - 3 ) - 271 i}{2 \cdot 7} : \frac{3}{14} - i \frac{271}{14}

The solutions to the quadratic equation are:

x = \frac{3}{14} + i \frac{271}{14}, x = \frac{3}{14} - i \frac{271}{14}

9 x^{2} - 42 x + 45 = 0

x^{2} + x - 48 = 0

z^{2} + 5 z - 3 = 0

5 x^{2} - 20 = 10 x

What are the solutions to the equation 7x^2-3x+10=0 ?
The solutions to the equation 7x^2-3x+10=0 are x= 3/14+i(sqrt(271))/(14),x= 3/14-i(sqrt(271))/(14)
Find the zeros of 7x^2-3x+10=0
The zeros of 7x^2-3x+10=0 are x= 3/14+i(sqrt(271))/(14),x= 3/14-i(sqrt(271))/(14)