What are the solutions to the equation 48x^2+12x-90=0 ?

The solutions to the equation 48x^2+12x-90=0 are x= 5/4 ,x=-3/2

Find the zeros of 48x^2+12x-90=0

The zeros of 48x^2+12x-90=0 are x= 5/4 ,x=-3/2

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48 x^{2} + 12 x - 90 = 0

x = \frac{5}{4}, x = - \frac{3}{2}

Decimal Notation

x = 1.25, x = - 1.5

Solution steps

48 x^{2} + 12 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 48 ( - 90 )}{2 \cdot 48}

1 2^{2} - 4 \cdot 48 (- 90) = 132

x_{1, 2} = \frac{- 12 \pm 132}{2 \cdot 48}

Separate the solutions

x_{1} = \frac{- 12 + 132}{2 \cdot 48}, x_{2} = \frac{- 12 - 132}{2 \cdot 48}

x = \frac{- 12 + 132}{2 \cdot 48} : \frac{5}{4}

x = \frac{- 12 - 132}{2 \cdot 48} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{3}{2}

x^{2} - 4 x + 2 = 10

x, 4 x^{2} + 4 y^{2} = 0

a, x^{2} + 2 a x + a^{2} = \frac{( x \cdot y )}{p}

2 (x - 3) (x + 10) = 0

4 x^{2} - 11 x + 6 = x^{2}

What are the solutions to the equation 48x^2+12x-90=0 ?
The solutions to the equation 48x^2+12x-90=0 are x= 5/4 ,x=-3/2
Find the zeros of 48x^2+12x-90=0
The zeros of 48x^2+12x-90=0 are x= 5/4 ,x=-3/2