What are the solutions to the equation 3(x-2)^2=12 ?

The solutions to the equation 3(x-2)^2=12 are x=4,x=0

Find the zeros of 3(x-2)^2=12

The zeros of 3(x-2)^2=12 are x=4,x=0

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3 (x - 2)^{2} = 12

x = 4, x = 0

Solution steps

3 (x - 2)^{2} = 12

Divide both sides by

3

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

x \cdot (x - 3) = 0

x^{2} - 5 x - 11 = - 7 x - 3

y^{2} - 2 y + 5

(4 x - 5)^{2} = 49

y^{2} - 4 y + 4 = 36

What are the solutions to the equation 3(x-2)^2=12 ?
The solutions to the equation 3(x-2)^2=12 are x=4,x=0
Find the zeros of 3(x-2)^2=12
The zeros of 3(x-2)^2=12 are x=4,x=0