What are the solutions to the equation (4x-5)^2=49 ?

The solutions to the equation (4x-5)^2=49 are x=3,x=-1/2

Find the zeros of (4x-5)^2=49

The zeros of (4x-5)^2=49 are x=3,x=-1/2

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(4 x - 5)^{2} = 49

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

(4 x - 5)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 5 = 49 : x = 3

Solve

4 x - 5 = - 49 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

y^{2} - 4 y + 4 = 36

7 x^{2} + 7 x = 0

6 (x^{2} - 1) = 5 x

a, a^{2} + b^{2} + c^{2} = d^{2}

x, x^{2} + y^{2} + 2 z^{2} - 4 x - 6 y = 0

What are the solutions to the equation (4x-5)^2=49 ?
The solutions to the equation (4x-5)^2=49 are x=3,x=-1/2
Find the zeros of (4x-5)^2=49
The zeros of (4x-5)^2=49 are x=3,x=-1/2