What are the solutions to the equation 6(x^2-1)=5x ?

The solutions to the equation 6(x^2-1)=5x are x= 3/2 ,x=-2/3

Find the zeros of 6(x^2-1)=5x

The zeros of 6(x^2-1)=5x are x= 3/2 ,x=-2/3

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6 (x^{2} - 1) = 5 x

x = \frac{3}{2}, x = - \frac{2}{3}

Decimal Notation

x = 1.5, x = - 0.66666 \dots

Solution steps

6 (x^{2} - 1) = 5 x

Expand

6 (x^{2} - 1) : 6 x^{2} - 6

6 x^{2} - 6 = 5 x

Move

5 x

to the left side

6 x^{2} - 6 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 6) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 6}

x = \frac{- ( - 5 ) + 13}{2 \cdot 6} : \frac{3}{2}

x = \frac{- ( - 5 ) - 13}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{2}{3}

a, a^{2} + b^{2} + c^{2} = d^{2}

x, x^{2} + y^{2} + 2 z^{2} - 4 x - 6 y = 0

2 x^{2} = 4 + x^{2}

m^{2} - 8 m + 17 = 0

525 = - 0.25 q^{2} + 750

What are the solutions to the equation 6(x^2-1)=5x ?
The solutions to the equation 6(x^2-1)=5x are x= 3/2 ,x=-2/3
Find the zeros of 6(x^2-1)=5x
The zeros of 6(x^2-1)=5x are x= 3/2 ,x=-2/3