What are the solutions to the equation r^2-8r+15=0 ?

The solutions to the equation r^2-8r+15=0 are r=5,r=3

Find the zeros of r^2-8r+15=0

The zeros of r^2-8r+15=0 are r=5,r=3

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r^{2} - 8 r + 15 = 0

r = 5, r = 3

Solution steps

r^{2} - 8 r + 15 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

r_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

r = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

r = 5, r = 3

1100 - x^{2} = 300 + x^{2}

120 = 5 (t)^{2}

d^{2} + 6 d + 5 = 0

x^{2} + 16 x = 5

x^{2} - 7 = 57

What are the solutions to the equation r^2-8r+15=0 ?
The solutions to the equation r^2-8r+15=0 are r=5,r=3
Find the zeros of r^2-8r+15=0
The zeros of r^2-8r+15=0 are r=5,r=3