What are the solutions to the equation x^2-4=4-2x ?

The solutions to the equation x^2-4=4-2x are x=2,x=-4

Find the zeros of x^2-4=4-2x

The zeros of x^2-4=4-2x are x=2,x=-4

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x^{2} - 4 = 4 - 2 x

x = 2, x = - 4

Solution steps

x^{2} - 4 = 4 - 2 x

Move

2 x

to the left side

x^{2} - 4 + 2 x = 4

Move

4

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

b^{2} + 3 b - 19 = - 5

4 c^{2} - 5 c - 6 = - 2

2 z^{2} - 13 z + 3 = - 4 z

6 x + 6 (x - 5) = x (x - 5)

y^{2} - y - 14 = 2 y

What are the solutions to the equation x^2-4=4-2x ?
The solutions to the equation x^2-4=4-2x are x=2,x=-4
Find the zeros of x^2-4=4-2x
The zeros of x^2-4=4-2x are x=2,x=-4