What are the solutions to the equation z^2-6z+25=0 ?

The solutions to the equation z^2-6z+25=0 are z=3+4i,z=3-4i

Find the zeros of z^2-6z+25=0

The zeros of z^2-6z+25=0 are z=3+4i,z=3-4i

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z^{2} - 6 z + 25 = 0

z = 3 + 4 i, z = 3 - 4 i

Solution steps

z^{2} - 6 z + 25 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 25 : 8 i

z_{1, 2} = \frac{- ( - 6 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 6 ) + 8 i}{2 \cdot 1}, z_{2} = \frac{- ( - 6 ) - 8 i}{2 \cdot 1}

z = \frac{- ( - 6 ) + 8 i}{2 \cdot 1} : 3 + 4 i

z = \frac{- ( - 6 ) - 8 i}{2 \cdot 1} : 3 - 4 i

The solutions to the quadratic equation are:

z = 3 + 4 i, z = 3 - 4 i

9 x^{2} + 4 x - \frac{4}{3} = 0

16 x^{2} - 24 x - 7 = 0

(x - 2) (x - a) = 0

7 x^{2} - 91 x = 0

X, 2 Y^{2} - X Y + X^{2} = 1

What are the solutions to the equation z^2-6z+25=0 ?
The solutions to the equation z^2-6z+25=0 are z=3+4i,z=3-4i
Find the zeros of z^2-6z+25=0
The zeros of z^2-6z+25=0 are z=3+4i,z=3-4i