What are the solutions to the equation 350+x-2x^2=50+x+x^2 ?

The solutions to the equation 350+x-2x^2=50+x+x^2 are x=10,x=-10

Find the zeros of 350+x-2x^2=50+x+x^2

The zeros of 350+x-2x^2=50+x+x^2 are x=10,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

350 + x - 2 x^{2} = 50 + x + x^{2}

x = 10, x = - 10

Solution steps

350 + x - 2 x^{2} = 50 + x + x^{2}

Move

350

to the right side

x - 2 x^{2} = x^{2} + x - 300

Move

x

to the left side

- 2 x^{2} = x^{2} - 300

Move

x^{2}

to the left side

- 3 x^{2} = - 300

Divide both sides by

- 3

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

x, y^{2} + 2 x y - x^{2} = 0

3 t^{2} - 5 t + 2 = 0

x (x + 3) = 5 x + 3

- 2 x^{2} + 10 x = 12

15 n^{2} + 41 n - 18 = 2 n

What are the solutions to the equation 350+x-2x^2=50+x+x^2 ?
The solutions to the equation 350+x-2x^2=50+x+x^2 are x=10,x=-10
Find the zeros of 350+x-2x^2=50+x+x^2
The zeros of 350+x-2x^2=50+x+x^2 are x=10,x=-10