What are the solutions to the equation x^2-2ax+1=0 ?

The solutions to the equation x^2-2ax+1=0 are x=a+sqrt(a^2-1),x=a-sqrt(a^2-1)

Find the zeros of x^2-2ax+1=0

The zeros of x^2-2ax+1=0 are x=a+sqrt(a^2-1),x=a-sqrt(a^2-1)

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x^{2} - 2 a x + 1 = 0

x = a + a^{2} - 1, x = a - a^{2} - 1

Solution steps

x^{2} - 2 a x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

(- 2 a)^{2} - 4 \cdot 1 \cdot 1 : 2 a^{2} - 1

x_{1, 2} = \frac{- ( - 2 a ) \pm 2 a ^{2} - 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 a ) + 2 a ^{2} - 1}{2 \cdot 1}, x_{2} = \frac{- ( - 2 a ) - 2 a ^{2} - 1}{2 \cdot 1}

x = \frac{- ( - 2 a ) + 2 a ^{2} - 1}{2 \cdot 1} : a + a^{2} - 1

x = \frac{- ( - 2 a ) - 2 a ^{2} - 1}{2 \cdot 1} : a - a^{2} - 1

The solutions to the quadratic equation are:

x = a + a^{2} - 1, x = a - a^{2} - 1

u^{2} + 9 = 0

x^{2} = 1 6^{2} - (83)^{2}

(4 x - 3)^{2} = 0

30 x^{2} - 18 x = 0

- x^{2} + 6 x - 8 = - 2 x^{2} + 8 x

What are the solutions to the equation x^2-2ax+1=0 ?
The solutions to the equation x^2-2ax+1=0 are x=a+sqrt(a^2-1),x=a-sqrt(a^2-1)
Find the zeros of x^2-2ax+1=0
The zeros of x^2-2ax+1=0 are x=a+sqrt(a^2-1),x=a-sqrt(a^2-1)