What are the solutions to the equation (4x-3)^2=0 ?

The solutions to the equation (4x-3)^2=0 are x= 3/4

Find the zeros of (4x-3)^2=0

The zeros of (4x-3)^2=0 are x= 3/4

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(4 x - 3)^{2} = 0

x = \frac{3}{4}

Decimal

x = 0.75

Solution steps

(4 x - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 x - 3 = 0 : x = \frac{3}{4}

The solution to the quadratic equation is:

x = \frac{3}{4}

30 x^{2} - 18 x = 0

- x^{2} + 6 x - 8 = - 2 x^{2} + 8 x

(2 x - 1) (3 x + 2) = 0

4 x^{2} + 13 x = 7

16 x^{2} - 3 x - 12 = 0

What are the solutions to the equation (4x-3)^2=0 ?
The solutions to the equation (4x-3)^2=0 are x= 3/4
Find the zeros of (4x-3)^2=0
The zeros of (4x-3)^2=0 are x= 3/4