What are the solutions to the equation (2x-1)(3x+2)=0 ?

The solutions to the equation (2x-1)(3x+2)=0 are x= 1/2 ,x=-2/3

Find the zeros of (2x-1)(3x+2)=0

The zeros of (2x-1)(3x+2)=0 are x= 1/2 ,x=-2/3

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(2 x - 1) (3 x + 2) = 0

x = \frac{1}{2}, x = - \frac{2}{3}

Decimal Notation

x = 0.5, x = - 0.66666 \dots

Solution steps

(2 x - 1) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 3 x + 2 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{2}{3}

4 x^{2} + 13 x = 7

16 x^{2} - 3 x - 12 = 0

(0.358393)^{2} + y^{2} = 1

5 x^{2} + 3 = 8 x + 7

4.9 x^{2} - 25 x - 50 = 0

What are the solutions to the equation (2x-1)(3x+2)=0 ?
The solutions to the equation (2x-1)(3x+2)=0 are x= 1/2 ,x=-2/3
Find the zeros of (2x-1)(3x+2)=0
The zeros of (2x-1)(3x+2)=0 are x= 1/2 ,x=-2/3