What are the solutions to the equation 16x^2-3x-12=0 ?

The solutions to the equation 16x^2-3x-12=0 are x=(3+sqrt(777))/(32),x=(3-sqrt(777))/(32)

Find the zeros of 16x^2-3x-12=0

The zeros of 16x^2-3x-12=0 are x=(3+sqrt(777))/(32),x=(3-sqrt(777))/(32)

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16 x^{2} - 3 x - 12 = 0

x = \frac{3 + 777}{32}, x = \frac{3 - 777}{32}

Decimal Notation

x = 0.96483 \dots, x = - 0.77733 \dots

Solution steps

16 x^{2} - 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 16 ( - 12 )}{2 \cdot 16}

(- 3)^{2} - 4 \cdot 16 (- 12) = 777

x_{1, 2} = \frac{- ( - 3 ) \pm 777}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 777}{2 \cdot 16}, x_{2} = \frac{- ( - 3 ) - 777}{2 \cdot 16}

x = \frac{- ( - 3 ) + 777}{2 \cdot 16} : \frac{3 + 777}{32}

x = \frac{- ( - 3 ) - 777}{2 \cdot 16} : \frac{3 - 777}{32}

The solutions to the quadratic equation are:

x = \frac{3 + 777}{32}, x = \frac{3 - 777}{32}

(0.358393)^{2} + y^{2} = 1

5 x^{2} + 3 = 8 x + 7

4.9 x^{2} - 25 x - 50 = 0

(x - 3)^{2} = - 103 + 28

33 + \frac{2 x ^{2}}{3} = 17

What are the solutions to the equation 16x^2-3x-12=0 ?
The solutions to the equation 16x^2-3x-12=0 are x=(3+sqrt(777))/(32),x=(3-sqrt(777))/(32)
Find the zeros of 16x^2-3x-12=0
The zeros of 16x^2-3x-12=0 are x=(3+sqrt(777))/(32),x=(3-sqrt(777))/(32)