What are the solutions to the equation x^2+(2-x)^2=884 ?

The solutions to the equation x^2+(2-x)^2=884 are x=22,x=-20

Find the zeros of x^2+(2-x)^2=884

The zeros of x^2+(2-x)^2=884 are x=22,x=-20

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x^{2} + (2 - x)^{2} = 884

x = 22, x = - 20

Solution steps

x^{2} + (2 - x)^{2} = 884

Expand

x^{2} + (2 - x)^{2} : 2 x^{2} - 4 x + 4

2 x^{2} - 4 x + 4 = 884

Move

884

to the left side

2 x^{2} - 4 x - 880 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 880 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 880) = 84

x_{1, 2} = \frac{- ( - 4 ) \pm 84}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 84}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 84}{2 \cdot 2}

x = \frac{- ( - 4 ) + 84}{2 \cdot 2} : 22

x = \frac{- ( - 4 ) - 84}{2 \cdot 2} : - 20

The solutions to the quadratic equation are:

x = 22, x = - 20

x, y^{2} x^{2} - 4 x^{2} = - y^{2} - 9

(2 x - 3)^{2} - (3 x + 1) (3 x - 1) = (x - 7) (x + 2) + 24

\frac{1}{2} x^{2} - x - 1 = - x + 1

13 t^{2} - 8 t + 1 = - 3 t^{2}

x, x^{2} + y^{2} + (z - 2)^{2} = 4

What are the solutions to the equation x^2+(2-x)^2=884 ?
The solutions to the equation x^2+(2-x)^2=884 are x=22,x=-20
Find the zeros of x^2+(2-x)^2=884
The zeros of x^2+(2-x)^2=884 are x=22,x=-20